Abe Mosseri wins WSOP Event #55 2-7 Triple Draw Lowball Limit
Thursday, 2 July 2009
Backgammon has often proved a great primer for poker players, just look at the success of Dan Harrington and Gus Hansen. And now the ranks have swelled further as former backgammon pro Abe Mosseri has won his first WSOP bracelet.
Mosseri outlasted a field of 258 players including to win the first prize of $165,521. The New Yorker beat a final table that included WSOP Europe winner John Juanda, Kill Phil author Blair Rodman and Julie Schneider, wife of 2007 WSOP Player of the Year winner Tom, before defeating Masayhoshi Tanaka heads up.
The win was Mosseri’s second cash at this year’s WSOP. He finished 6th in the Seven Card Stud Hi-Lo. Other big names to make the money included Justin Smith, Daniel Negreanu, Nam Le and Ali Sarkeshik.
The final table positions and payouts were as follows:
1 Abe Mosseri $165,521
2 Masayhoshi Tanaka $102,313
3 Julia Schneider $66,285
4 John Juanda $44,941
5 Blair Rodman $31,818
6 Brad Libson $23,484
TAGS: Poker News, Abe, Mosseri, wins, WSOP, Event, #55, 2-7, Triple, Draw, Lowball, Limit